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11312333110231 is a prime number
BaseRepresentation
bin1010010010011101101110…
…0110001011101111010111
31111001110002221111121201221
42210213123212023233113
52440320124234011411
640020451502031211
72245201105623406
oct244473346135727
944043087447657
1011312333110231
11367159614649a
1213284a5578507
13640996408b0a
142b173c64763d
151493d6988071
hexa49db98bbd7

11312333110231 has 2 divisors, whose sum is σ = 11312333110232. Its totient is φ = 11312333110230.

The previous prime is 11312333110229. The next prime is 11312333110289. The reversal of 11312333110231 is 13201133321311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11312333110231 - 21 = 11312333110229 is a prime.

It is a super-2 number, since 2×113123331102312 (a number of 27 digits) contains 22 as substring.

Together with 11312333110229, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11312333110196 and 11312333110205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312330110231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656166555115 + 5656166555116.

It is an arithmetic number, because the mean of its divisors is an integer number (5656166555116).

Almost surely, 211312333110231 is an apocalyptic number.

11312333110231 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312333110231 is an equidigital number, since it uses as much as digits as its factorization.

11312333110231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11312333110231 its reverse (13201133321311), we get a palindrome (24513466431542).

The spelling of 11312333110231 in words is "eleven trillion, three hundred twelve billion, three hundred thirty-three million, one hundred ten thousand, two hundred thirty-one".