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113123440313200 = 24522375135574603
BaseRepresentation
bin11001101110001010011010…
…011110011100001101110000
3112211112111101001112200120001
4121232022122132130031300
5104311403301210010300
61040332105133355344
732553620210234662
oct3156123236341560
9484474331480501
10113123440313200
1133054421a31239
12108300b7338b54
134b176579877b5
141dd12bd042532
15d12900e7916a
hex66e29a79c370

113123440313200 has 240 divisors, whose sum is σ = 284114715780096. Its totient is φ = 43202839680000.

The previous prime is 113123440313167. The next prime is 113123440313231. The reversal of 113123440313200 is 2313044321311.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 24576022099 + ... + 24576026701.

Almost surely, 2113123440313200 is an apocalyptic number.

113123440313200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113123440313200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (142057357890048).

113123440313200 is an abundant number, since it is smaller than the sum of its proper divisors (170991275466896).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113123440313200 is a wasteful number, since it uses less digits than its factorization.

113123440313200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8952 (or 8941 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 113123440313200 its reverse (2313044321311), we get a palindrome (115436484634511).

The spelling of 113123440313200 in words is "one hundred thirteen trillion, one hundred twenty-three billion, four hundred forty million, three hundred thirteen thousand, two hundred".