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11312344151 is a prime number
BaseRepresentation
bin10101000100100010…
…01010110001010111
31002012101011121212022
422202101022301113
5141131430003101
65110302443355
7550221224123
oct124221126127
932171147768
1011312344151
114885583659
12223859355b
1310b3857c84
14794578583
154631daa1b
hex2a244ac57

11312344151 has 2 divisors, whose sum is σ = 11312344152. Its totient is φ = 11312344150.

The previous prime is 11312344139. The next prime is 11312344163. The reversal of 11312344151 is 15144321311.

It is a balanced prime because it is at equal distance from previous prime (11312344139) and next prime (11312344163).

It is a cyclic number.

It is not a de Polignac number, because 11312344151 - 210 = 11312343127 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11312344151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312344111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656172075 + 5656172076.

It is an arithmetic number, because the mean of its divisors is an integer number (5656172076).

Almost surely, 211312344151 is an apocalyptic number.

11312344151 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312344151 is an equidigital number, since it uses as much as digits as its factorization.

11312344151 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 26.

Adding to 11312344151 its reverse (15144321311), we get a palindrome (26456665462).

The spelling of 11312344151 in words is "eleven billion, three hundred twelve million, three hundred forty-four thousand, one hundred fifty-one".