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1131240035453 = 11143217181063
BaseRepresentation
bin10000011101100011001…
…010010001010001111101
311000010221001200222221212
4100131203022101101331
5122013234422113303
62223403503534205
7144505116435053
oct20354312212175
94003831628855
101131240035453
113a6835566010
121632a9bba365
13828a2041558
143ca764a41d3
151e65d3c2ad8
hex1076329147d

1131240035453 has 8 divisors (see below), whose sum is σ = 1234166383296. Its totient is φ = 1028328078400.

The previous prime is 1131240035413. The next prime is 1131240035461. The reversal of 1131240035453 is 3545300421311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1131240035453 - 28 = 1131240035197 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131240035413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3433001 + ... + 3748062.

It is an arithmetic number, because the mean of its divisors is an integer number (154270797912).

Almost surely, 21131240035453 is an apocalyptic number.

It is an amenable number.

1131240035453 is a deficient number, since it is larger than the sum of its proper divisors (102926347843).

1131240035453 is a wasteful number, since it uses less digits than its factorization.

1131240035453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7195395.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 1131240035453 its reverse (3545300421311), we get a palindrome (4676540456764).

The spelling of 1131240035453 in words is "one trillion, one hundred thirty-one billion, two hundred forty million, thirty-five thousand, four hundred fifty-three".

Divisors: 1 11 14321 157531 7181063 78991693 102840003223 1131240035453