Base | Representation |
---|---|
bin | 1010010010011110000001… |
… | …1011001001001001111100 |
3 | 1111001110022120220102202021 |
4 | 2210213200123021021330 |
5 | 2440320311002232030 |
6 | 40020503514005524 |
7 | 2245203111220414 |
oct | 244474033111174 |
9 | 44043276812667 |
10 | 11312414102140 |
11 | 3671627934958 |
12 | 13285087168a4 |
13 | 6409aa125818 |
14 | 2b17492cb644 |
15 | 1493ddb3597a |
hex | a49e06c927c |
11312414102140 has 24 divisors (see below), whose sum is σ = 24522394442112. Its totient is φ = 4378999007040.
The previous prime is 11312414102063. The next prime is 11312414102141. The reversal of 11312414102140 is 4120141421311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11312414102141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9122913979 + ... + 9122915218.
It is an arithmetic number, because the mean of its divisors is an integer number (1021766435088).
Almost surely, 211312414102140 is an apocalyptic number.
11312414102140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11312414102140 is an abundant number, since it is smaller than the sum of its proper divisors (13209980339972).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11312414102140 is a wasteful number, since it uses less digits than its factorization.
11312414102140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18245829237 (or 18245829235 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 11312414102140 its reverse (4120141421311), we get a palindrome (15432555523451).
The spelling of 11312414102140 in words is "eleven trillion, three hundred twelve billion, four hundred fourteen million, one hundred two thousand, one hundred forty".
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