Base | Representation |
---|---|
bin | 10000011101100011100… |
… | …011100001001011000001 |
3 | 11000010221112011021002121 |
4 | 100131203203201023001 |
5 | 122013243120413040 |
6 | 2223404301444241 |
7 | 144505226622406 |
oct | 20354343411301 |
9 | 4003845137077 |
10 | 1131246654145 |
11 | 3a6839276803 |
12 | 1632b0270681 |
13 | 828a351b03a |
14 | 3ca773082ad |
15 | 1e65dc7dc4a |
hex | 107638e12c1 |
1131246654145 has 4 divisors (see below), whose sum is σ = 1357495984980. Its totient is φ = 904997323312.
The previous prime is 1131246654133. The next prime is 1131246654211. The reversal of 1131246654145 is 5414566421311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 874671987121 + 256574667024 = 935239^2 + 506532^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131246654145 - 219 = 1131246129857 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113124665410 + ... + 113124665419.
It is an arithmetic number, because the mean of its divisors is an integer number (339373996245).
Almost surely, 21131246654145 is an apocalyptic number.
It is an amenable number.
1131246654145 is a deficient number, since it is larger than the sum of its proper divisors (226249330835).
1131246654145 is an equidigital number, since it uses as much as digits as its factorization.
1131246654145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 226249330834.
The product of its digits is 345600, while the sum is 43.
The spelling of 1131246654145 in words is "one trillion, one hundred thirty-one billion, two hundred forty-six million, six hundred fifty-four thousand, one hundred forty-five".
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