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11312555341 is a prime number
BaseRepresentation
bin10101000100100011…
…11110010101001101
31002012101120100120011
422202101332111031
5141132003232331
65110311153221
7550223063623
oct124221762515
932171510504
1011312555341
11488570829a
122238675811
1310b3900139
147945d1513
1546322d3b1
hex2a247e54d

11312555341 has 2 divisors, whose sum is σ = 11312555342. Its totient is φ = 11312555340.

The previous prime is 11312555323. The next prime is 11312555411. The reversal of 11312555341 is 14355521311.

11312555341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11211633225 + 100922116 = 105885^2 + 10046^2 .

It is a cyclic number.

It is not a de Polignac number, because 11312555341 - 29 = 11312554829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312555311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656277670 + 5656277671.

It is an arithmetic number, because the mean of its divisors is an integer number (5656277671).

Almost surely, 211312555341 is an apocalyptic number.

It is an amenable number.

11312555341 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312555341 is an equidigital number, since it uses as much as digits as its factorization.

11312555341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9000, while the sum is 31.

The spelling of 11312555341 in words is "eleven billion, three hundred twelve million, five hundred fifty-five thousand, three hundred forty-one".