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113130000002 = 256565000001
BaseRepresentation
bin110100101011100010…
…0101100111010000010
3101211000020001110012002
41221113010230322002
53323142240000002
6123545440304002
711113316063615
oct1512704547202
9354006043162
10113130000002
1143a83a32478
1219b13012002
13a88bac9c06
145692b8a17c
152e21cba002
hex1a5712ce82

113130000002 has 4 divisors (see below), whose sum is σ = 169695000006. Its totient is φ = 56565000000.

The previous prime is 113129999987. The next prime is 113130000023. The reversal of 113130000002 is 200000031311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 95424770281 + 17705229721 = 308909^2 + 133061^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28282499999 + ... + 28282500002.

Almost surely, 2113130000002 is an apocalyptic number.

113130000002 is a deficient number, since it is larger than the sum of its proper divisors (56565000004).

113130000002 is an equidigital number, since it uses as much as digits as its factorization.

113130000002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56565000003.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 113130000002 its reverse (200000031311), we get a palindrome (313130031313).

The spelling of 113130000002 in words is "one hundred thirteen billion, one hundred thirty million, two", and thus it is an aban number.

Divisors: 1 2 56565000001 113130000002