Base | Representation |
---|---|
bin | 11001101110010000100010… |
… | …001000110001000100001011 |
3 | 112211120010100000000102000111 |
4 | 121232100202020301010023 |
5 | 104312010230343100412 |
6 | 1040335113144415151 |
7 | 32554242066554134 |
oct | 3156204210610413 |
9 | 484503300012014 |
10 | 113130011300107 |
11 | 330571940a3a2a |
12 | 1083142ba774b7 |
13 | 4b18164131429 |
14 | 1dd1743a04c8b |
15 | d12b87c9d2a7 |
hex | 66e42223110b |
113130011300107 has 2 divisors, whose sum is σ = 113130011300108. Its totient is φ = 113130011300106.
The previous prime is 113130011300087. The next prime is 113130011300113. The reversal of 113130011300107 is 701003110031311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113130011300107 - 27 = 113130011299979 is a prime.
It is a super-2 number, since 2×1131300113001072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113130011306107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565005650053 + 56565005650054.
It is an arithmetic number, because the mean of its divisors is an integer number (56565005650054).
Almost surely, 2113130011300107 is an apocalyptic number.
113130011300107 is a deficient number, since it is larger than the sum of its proper divisors (1).
113130011300107 is an equidigital number, since it uses as much as digits as its factorization.
113130011300107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 189, while the sum is 22.
Adding to 113130011300107 its reverse (701003110031311), we get a palindrome (814133121331418).
The spelling of 113130011300107 in words is "one hundred thirteen trillion, one hundred thirty billion, eleven million, three hundred thousand, one hundred seven".
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