113130011300113 has 2 divisors, whose sum is σ = 113130011300114. Its totient is φ = 113130011300112.

The previous prime is 113130011300107. The next prime is 113130011300153. The reversal of 113130011300113 is 311003110031311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113040955013184 + 89056286929 = 10632072^2 + 298423^2 .

It is a cyclic number.

It is not a de Polignac number, because 113130011300113 - 2⁹ = 113130011299601 is a prime.

It is not a weakly prime, because it can be changed into another prime (113130011300153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565005650056 + 56565005650057.

It is an arithmetic number, because the mean of its divisors is an integer number (56565005650057).

Almost surely, 2^{113130011300113} is an apocalyptic number.

It is an amenable number.

113130011300113 is a deficient number, since it is larger than the sum of its proper divisors (1).

113130011300113 is an equidigital number, since it uses as much as digits as its factorization.

113130011300113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 113130011300113 its reverse (311003110031311), we get a palindrome (424133121331424).

The spelling of 113130011300113 in words is "one hundred thirteen trillion, one hundred thirty billion, eleven million, three hundred thousand, one hundred thirteen".