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113130031312 = 247070626957
BaseRepresentation
bin110100101011100010…
…0110100100011010000
3101211000020010001010201
41221113010310203100
53323142242000222
6123545441104544
711113316254114
oct1512704644320
9354006101121
10113130031312
1143a83a53a51
1219b13028154
13a88bb0b23c
145692b97744
152e21cc4427
hex1a571348d0

113130031312 has 10 divisors (see below), whose sum is σ = 219189435698. Its totient is φ = 56565015648.

The previous prime is 113130031309. The next prime is 113130031331. The reversal of 113130031312 is 213130031311.

It can be written as a sum of positive squares in only one way, i.e., 70604992656 + 42525038656 = 265716^2 + 206216^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 113130031312.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3535313463 + ... + 3535313494.

Almost surely, 2113130031312 is an apocalyptic number.

It is an amenable number.

113130031312 is a deficient number, since it is larger than the sum of its proper divisors (106059404386).

113130031312 is an equidigital number, since it uses as much as digits as its factorization.

113130031312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7070626965 (or 7070626959 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 113130031312 its reverse (213130031311), we get a palindrome (326260062623).

Subtracting 113130031312 from its reverse (213130031311), we obtain a palindrome (99999999999).

The spelling of 113130031312 in words is "one hundred thirteen billion, one hundred thirty million, thirty-one thousand, three hundred twelve".

Divisors: 1 2 4 8 16 7070626957 14141253914 28282507828 56565015656 113130031312