Base | Representation |
---|---|
bin | 110100101011100010… |
… | …1001000000001000111 |
3 | 101211000020021002111212 |
4 | 1221113011020001013 |
5 | 3323142302023142 |
6 | 123545442522035 |
7 | 11113320035432 |
oct | 1512705100107 |
9 | 354006232455 |
10 | 113130111047 |
11 | 43a83aa8948 |
12 | 19b1306631b |
13 | a88bb38615 |
14 | 5692bb8819 |
15 | 2e21cdcd82 |
hex | 1a57148047 |
113130111047 has 2 divisors, whose sum is σ = 113130111048. Its totient is φ = 113130111046.
The previous prime is 113130110957. The next prime is 113130111151. The reversal of 113130111047 is 740111031311.
It is a weak prime.
It is an emirp because it is prime and its reverse (740111031311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113130111047 - 212 = 113130106951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113120111047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565055523 + 56565055524.
It is an arithmetic number, because the mean of its divisors is an integer number (56565055524).
Almost surely, 2113130111047 is an apocalyptic number.
113130111047 is a deficient number, since it is larger than the sum of its proper divisors (1).
113130111047 is an equidigital number, since it uses as much as digits as its factorization.
113130111047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 23.
Adding to 113130111047 its reverse (740111031311), we get a palindrome (853241142358).
The spelling of 113130111047 in words is "one hundred thirteen billion, one hundred thirty million, one hundred eleven thousand, forty-seven".
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