113130141 has 4 divisors (see below), whose sum is σ = 150840192. Its totient is φ = 75420092.

The previous prime is 113130113. The next prime is 113130151. The reversal of 113130141 is 141031311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 141031311 = 3 ⋅47010437.

It is a cyclic number.

It is not a de Polignac number, because 113130141 - 2⁵ = 113130109 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 113130141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113130151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18855021 + ... + 18855026.

It is an arithmetic number, because the mean of its divisors is an integer number (37710048).

Almost surely, 2^113130141 is an apocalyptic number.

It is an amenable number.

113130141 is a deficient number, since it is larger than the sum of its proper divisors (37710051).

113130141 is an equidigital number, since it uses as much as digits as its factorization.

113130141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37710050.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 113130141 is about 10636.2653690099. The cubic root of 113130141 is about 483.6443397756.

Adding to 113130141 its reverse (141031311), we get a palindrome (254161452).

The spelling of 113130141 in words is "one hundred thirteen million, one hundred thirty thousand, one hundred forty-one".