Base | Representation |
---|---|
bin | 10101000100100111… |
… | …10000000110101001 |
3 | 1002012102110000210212 |
4 | 22202103300012221 |
5 | 141132113140403 |
6 | 5110325150505 |
7 | 550230044354 |
oct | 124223600651 |
9 | 32172400725 |
10 | 11313021353 |
11 | 48859a6427 |
12 | 223885b435 |
13 | 10b3a3429a |
14 | 7946b329b |
15 | 4632c14d8 |
hex | 2a24f01a9 |
11313021353 has 2 divisors, whose sum is σ = 11313021354. Its totient is φ = 11313021352.
The previous prime is 11313021341. The next prime is 11313021367. The reversal of 11313021353 is 35312031311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10533327424 + 779693929 = 102632^2 + 27923^2 .
It is an emirp because it is prime and its reverse (35312031311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11313021353 - 230 = 10239279529 is a prime.
It is not a weakly prime, because it can be changed into another prime (11313021373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656510676 + 5656510677.
It is an arithmetic number, because the mean of its divisors is an integer number (5656510677).
Almost surely, 211313021353 is an apocalyptic number.
It is an amenable number.
11313021353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313021353 is an equidigital number, since it uses as much as digits as its factorization.
11313021353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 11313021353 its reverse (35312031311), we get a palindrome (46625052664).
The spelling of 11313021353 in words is "eleven billion, three hundred thirteen million, twenty-one thousand, three hundred fifty-three".
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