Base | Representation |
---|---|
bin | 10101000100100111… |
… | …10000000110011101 |
3 | 1002012102110000210102 |
4 | 22202103300012131 |
5 | 141132113140331 |
6 | 5110325150445 |
7 | 550230044336 |
oct | 124223600635 |
9 | 32172400712 |
10 | 11313021341 |
11 | 48859a6416 |
12 | 223885b425 |
13 | 10b3a3428b |
14 | 7946b328d |
15 | 4632c14cb |
hex | 2a24f019d |
11313021341 has 2 divisors, whose sum is σ = 11313021342. Its totient is φ = 11313021340.
The previous prime is 11313021283. The next prime is 11313021353. The reversal of 11313021341 is 14312031311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8839948441 + 2473072900 = 94021^2 + 49730^2 .
It is a cyclic number.
It is not a de Polignac number, because 11313021341 - 214 = 11313004957 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313029341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656510670 + 5656510671.
It is an arithmetic number, because the mean of its divisors is an integer number (5656510671).
Almost surely, 211313021341 is an apocalyptic number.
It is an amenable number.
11313021341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313021341 is an equidigital number, since it uses as much as digits as its factorization.
11313021341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11313021341 its reverse (14312031311), we get a palindrome (25625052652).
The spelling of 11313021341 in words is "eleven billion, three hundred thirteen million, twenty-one thousand, three hundred forty-one".
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