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113130340003 = 296073642359
BaseRepresentation
bin110100101011100010…
…1111111111010100011
3101211000020200201120201
41221113011333322203
53323142331340003
6123545451450031
711113322011102
oct1512705777243
9354006621521
10113130340003
1143a8414496a
1219b13156917
13a88bbb88b5
145692c38039
152e21d35b1d
hex1a5717fea3

113130340003 has 8 divisors (see below), whose sum is σ = 117050839200. Its totient is φ = 109211137728.

The previous prime is 113130339991. The next prime is 113130340019. The reversal of 113130340003 is 300043031311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113130340003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113130340703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 145063 + ... + 497296.

It is an arithmetic number, because the mean of its divisors is an integer number (14631354900).

Almost surely, 2113130340003 is an apocalyptic number.

113130340003 is a deficient number, since it is larger than the sum of its proper divisors (3920499197).

113130340003 is an equidigital number, since it uses as much as digits as its factorization.

113130340003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 648461.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 113130340003 its reverse (300043031311), we get a palindrome (413173371314).

The spelling of 113130340003 in words is "one hundred thirteen billion, one hundred thirty million, three hundred forty thousand, three".

Divisors: 1 29 6073 176117 642359 18628411 3901046207 113130340003