Base | Representation |
---|---|
bin | 10101000100100111… |
… | …10100101110111001 |
3 | 1002012102110222211002 |
4 | 22202103310232321 |
5 | 141132114242223 |
6 | 5110325414345 |
7 | 550230153551 |
oct | 124223645671 |
9 | 32172428732 |
10 | 11313040313 |
11 | 4885a096a3 |
12 | 223886a3b5 |
13 | 10b3a3cac3 |
14 | 7946ba161 |
15 | 4632c6e28 |
hex | 2a24f4bb9 |
11313040313 has 6 divisors (see below), whose sum is σ = 11414054574. Its totient is φ = 11212912256.
The previous prime is 11313040309. The next prime is 11313040393. The reversal of 11313040313 is 31304031311.
It can be written as a sum of positive squares in 3 ways, for example, as 3328366864 + 7984673449 = 57692^2 + 89357^2 .
It is not a de Polignac number, because 11313040313 - 22 = 11313040309 is a prime.
It is a super-2 number, since 2×113130403132 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11313040393) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 430220 + ... + 455757.
It is an arithmetic number, because the mean of its divisors is an integer number (1902342429).
Almost surely, 211313040313 is an apocalyptic number.
It is an amenable number.
11313040313 is a deficient number, since it is larger than the sum of its proper divisors (101014261).
11313040313 is an frugal number, since it uses more digits than its factorization.
11313040313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 886203 (or 886090 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 11313040313 its reverse (31304031311), we get a palindrome (42617071624).
It can be divided in two parts, 11 and 313040313, that multiplied together give a palindrome (3443443443).
The spelling of 11313040313 in words is "eleven billion, three hundred thirteen million, forty thousand, three hundred thirteen".
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