1131304444231 has 4 divisors (see below), whose sum is σ = 1218327863032. Its totient is φ = 1044281025432.

The previous prime is 1131304444229. The next prime is 1131304444261. The reversal of 1131304444231 is 1324444031311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131304444231 - 2¹ = 1131304444229 is a prime.

It is a super-2 number, since 2×1131304444231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131304444193 and 1131304444202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131304444261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43511709381 + ... + 43511709406.

It is an arithmetic number, because the mean of its divisors is an integer number (304581965758).

Almost surely, 2^{1131304444231} is an apocalyptic number.

1131304444231 is a deficient number, since it is larger than the sum of its proper divisors (87023418801).

1131304444231 is an equidigital number, since it uses as much as digits as its factorization.

1131304444231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87023418800.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1131304444231 its reverse (1324444031311), we get a palindrome (2455748475542).

The spelling of 1131304444231 in words is "one trillion, one hundred thirty-one billion, three hundred four million, four hundred forty-four thousand, two hundred thirty-one".