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11313049540800 = 26352717131151189
BaseRepresentation
bin1010010010100000011001…
…0011001001100011000000
31111001111221212121001201110
42210220012103021203000
52440323111140301200
640021050533403320
72245224625316310
oct244500623114300
944044855531643
1011313049540800
113671923598377
121328665499540
13640a7b97ba27
142b17a985b440
15149429803b50
hexa4a064c98c0

11313049540800 has 672 divisors, whose sum is σ = 45256909800960. Its totient is φ = 2415137587200.

The previous prime is 11313049540787. The next prime is 11313049540801. The reversal of 11313049540800 is 804594031311.

It is a tau number, because it is divible by the number of its divisors (672).

It is not an unprimeable number, because it can be changed into a prime (11313049540801) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 74751606 + ... + 74902794.

Almost surely, 211313049540800 is an apocalyptic number.

11313049540800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313049540800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22628454900480).

11313049540800 is an abundant number, since it is smaller than the sum of its proper divisors (33943860260160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313049540800 is a wasteful number, since it uses less digits than its factorization.

11313049540800 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 151369 (or 151354 counting only the distinct ones).

The product of its (nonzero) digits is 51840, while the sum is 39.

The spelling of 11313049540800 in words is "eleven trillion, three hundred thirteen billion, forty-nine million, five hundred forty thousand, eight hundred".