Base | Representation |
---|---|
bin | 10101000100101000… |
… | …00011010110111111 |
3 | 1002012102121000222222 |
4 | 22202110003112333 |
5 | 141132123201343 |
6 | 5110330555555 |
7 | 550230523325 |
oct | 124224032677 |
9 | 32172530888 |
10 | 11313100223 |
11 | 4885a4a707 |
12 | 2238898bbb |
13 | 10b3a61159 |
14 | 7946d3d15 |
15 | 4632d9a68 |
hex | 2a25035bf |
11313100223 has 2 divisors, whose sum is σ = 11313100224. Its totient is φ = 11313100222.
The previous prime is 11313100219. The next prime is 11313100237. The reversal of 11313100223 is 32200131311.
11313100223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (32200131311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11313100223 - 22 = 11313100219 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313100243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656550111 + 5656550112.
It is an arithmetic number, because the mean of its divisors is an integer number (5656550112).
Almost surely, 211313100223 is an apocalyptic number.
11313100223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313100223 is an equidigital number, since it uses as much as digits as its factorization.
11313100223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11313100223 its reverse (32200131311), we get a palindrome (43513231534).
The spelling of 11313100223 in words is "eleven billion, three hundred thirteen million, one hundred thousand, two hundred twenty-three".
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