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113131003200 = 2635231760289
BaseRepresentation
bin110100101011100100…
…0100001110101000000
3101211000021221102022120
41221113020201311000
53323143014100300
6123545514004240
711113330442445
oct1512710416500
9354007842276
10113131003200
1143a84558166
1219b13416680
13a88c08b717
145692d6b9cc
152e21e173a0
hex1a57221d40

113131003200 has 168 divisors, whose sum is σ = 383137501440. Its totient is φ = 29195059200.

The previous prime is 113131003159. The next prime is 113131003217. The reversal of 113131003200 is 2300131311.

113131003200 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 113131003200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 231345 + ... + 528944.

Almost surely, 2113131003200 is an apocalyptic number.

113131003200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113131003200 is an abundant number, since it is smaller than the sum of its proper divisors (270006498240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113131003200 is a wasteful number, since it uses less digits than its factorization.

113131003200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 760345 (or 760330 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 113131003200 its reverse (2300131311), we get a palindrome (115431134511).

The spelling of 113131003200 in words is "one hundred thirteen billion, one hundred thirty-one million, three thousand, two hundred".