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11313106697 is a prime number
BaseRepresentation
bin10101000100101000…
…00100111100001001
31002012102121100212202
422202110010330021
5141132123403242
65110331045545
7550230551234
oct124224047411
932172540782
1011313106697
114885a54562
1222388a08b5
1310b3a64099
147946d641b
154632db932
hex2a2504f09

11313106697 has 2 divisors, whose sum is σ = 11313106698. Its totient is φ = 11313106696.

The previous prime is 11313106691. The next prime is 11313106699. The reversal of 11313106697 is 79660131311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7787003536 + 3526103161 = 88244^2 + 59381^2 .

It is an emirp because it is prime and its reverse (79660131311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11313106697 - 24 = 11313106681 is a prime.

Together with 11313106699, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11313106697.

It is not a weakly prime, because it can be changed into another prime (11313106691) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656553348 + 5656553349.

It is an arithmetic number, because the mean of its divisors is an integer number (5656553349).

Almost surely, 211313106697 is an apocalyptic number.

It is an amenable number.

11313106697 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313106697 is an equidigital number, since it uses as much as digits as its factorization.

11313106697 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20412, while the sum is 38.

The spelling of 11313106697 in words is "eleven billion, three hundred thirteen million, one hundred six thousand, six hundred ninety-seven".