Base | Representation |
---|---|
bin | 1010010010100000100111… |
… | …1010100110000111101100 |
3 | 1111001112010002202112110200 |
4 | 2210220021322212013230 |
5 | 2440323222203304400 |
6 | 40021100542033500 |
7 | 2245226263113423 |
oct | 244501172460754 |
9 | 44045102675420 |
10 | 11313110213100 |
11 | 3671954868373 |
12 | 1328681878890 |
13 | 640a8b4029b7 |
14 | 2b17b39322ba |
15 | 14942ecdab00 |
hex | a4a09ea61ec |
11313110213100 has 108 divisors (see below), whose sum is σ = 35858746221480. Its totient is φ = 2982932409600.
The previous prime is 11313110213089. The next prime is 11313110213131. The reversal of 11313110213100 is 131201131311.
11313110213100 is a `hidden beast` number, since 1 + 131 + 311 + 0 + 213 + 10 + 0 = 666.
It is a super-2 number, since 2×113131102131002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 70538566 + ... + 70698765.
Almost surely, 211313110213100 is an apocalyptic number.
11313110213100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11313110213100 is an abundant number, since it is smaller than the sum of its proper divisors (24545636008380).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313110213100 is a wasteful number, since it uses less digits than its factorization.
11313110213100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 141237440 (or 141237430 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 11313110213100 its reverse (131201131311), we get a palindrome (11444311344411).
The spelling of 11313110213100 in words is "eleven trillion, three hundred thirteen billion, one hundred ten million, two hundred thirteen thousand, one hundred".
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