Base | Representation |
---|---|
bin | 1010010010100000101000… |
… | …0010010000001010001111 |
3 | 1111001112010020112111211112 |
4 | 2210220022002100022033 |
5 | 2440323223212022203 |
6 | 40021101053042235 |
7 | 2245226316143345 |
oct | 244501202201217 |
9 | 44045106474745 |
10 | 11313112220303 |
11 | 3671955a09413 |
12 | 132868248637b |
13 | 640a8b9564aa |
14 | 2b17b3cd5995 |
15 | 1494300856d8 |
hex | a4a0a09028f |
11313112220303 has 12 divisors (see below), whose sum is σ = 11888290796928. Its totient is φ = 10764581984640.
The previous prime is 11313112220279. The next prime is 11313112220323. The reversal of 11313112220303 is 30302221131311.
It is not a de Polignac number, because 11313112220303 - 212 = 11313112216207 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313112220323) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 55882850 + ... + 56084927.
It is an arithmetic number, because the mean of its divisors is an integer number (990690899744).
Almost surely, 211313112220303 is an apocalyptic number.
11313112220303 is a deficient number, since it is larger than the sum of its proper divisors (575178576625).
11313112220303 is a wasteful number, since it uses less digits than its factorization.
11313112220303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 111968014 (or 111967991 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11313112220303 its reverse (30302221131311), we get a palindrome (41615333351614).
The spelling of 11313112220303 in words is "eleven trillion, three hundred thirteen billion, one hundred twelve million, two hundred twenty thousand, three hundred three".
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