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113131210000 = 245461191971
BaseRepresentation
bin110100101011100100…
…1010100010100010000
3101211000022022220222211
41221113021110110100
53323143042210000
6123545522241504
711113332263404
oct1512711242420
9354008286884
10113131210000
1143a84689576
1219b134b6294
13a88c1318a3
145692dc3104
152e21e587ba
hex1a57254510

113131210000 has 200 divisors, whose sum is σ = 280137927168. Its totient is φ = 44232000000.

The previous prime is 113131209991. The next prime is 113131210021. The reversal of 113131210000 is 12131311.

It is a tau number, because it is divible by the number of its divisors (200).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 116509515 + ... + 116510485.

Almost surely, 2113131210000 is an apocalyptic number.

113131210000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113131210000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (140068963584).

113131210000 is an abundant number, since it is smaller than the sum of its proper divisors (167006717168).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113131210000 is an equidigital number, since it uses as much as digits as its factorization.

113131210000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1251 (or 1230 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 113131210000 its reverse (12131311), we get a palindrome (113143341311).

The spelling of 113131210000 in words is "one hundred thirteen billion, one hundred thirty-one million, two hundred ten thousand".