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113131212302 = 256565606151
BaseRepresentation
bin110100101011100100…
…1010100111000001110
3101211000022100001011002
41221113021110320032
53323143042243202
6123545522300302
711113332303203
oct1512711247016
9354008301132
10113131212302
1143a84690279
1219b134b7692
13a88c132954
145692dc3caa
152e21e59302
hex1a57254e0e

113131212302 has 4 divisors (see below), whose sum is σ = 169696818456. Its totient is φ = 56565606150.

The previous prime is 113131212287. The next prime is 113131212317. The reversal of 113131212302 is 203212131311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (113131212287) and next prime (113131212317).

It is a super-2 number, since 2×1131312123022 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28282803074 + ... + 28282803077.

It is an arithmetic number, because the mean of its divisors is an integer number (42424204614).

Almost surely, 2113131212302 is an apocalyptic number.

113131212302 is a deficient number, since it is larger than the sum of its proper divisors (56565606154).

113131212302 is an equidigital number, since it uses as much as digits as its factorization.

113131212302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56565606153.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 113131212302 its reverse (203212131311), we get a palindrome (316343343613).

The spelling of 113131212302 in words is "one hundred thirteen billion, one hundred thirty-one million, two hundred twelve thousand, three hundred two".

Divisors: 1 2 56565606151 113131212302