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11313122129 is a prime number
BaseRepresentation
bin10101000100101000…
…01000101101010001
31002012102122011001022
422202110020231101
5141132124402004
65110331245225
7550230644231
oct124224105521
932172564038
1011313122129
114885a65111
1222388a9815
1310b3a6b10a
147946dbcc1
154632e12be
hex2a2508b51

11313122129 has 2 divisors, whose sum is σ = 11313122130. Its totient is φ = 11313122128.

The previous prime is 11313122069. The next prime is 11313122131. The reversal of 11313122129 is 92122131311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10994571025 + 318551104 = 104855^2 + 17848^2 .

It is a cyclic number.

It is not a de Polignac number, because 11313122129 - 228 = 11044686673 is a prime.

Together with 11313122131, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11313122098 and 11313122107.

It is not a weakly prime, because it can be changed into another prime (11313124129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656561064 + 5656561065.

It is an arithmetic number, because the mean of its divisors is an integer number (5656561065).

Almost surely, 211313122129 is an apocalyptic number.

It is an amenable number.

11313122129 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313122129 is an equidigital number, since it uses as much as digits as its factorization.

11313122129 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 648, while the sum is 26.

The spelling of 11313122129 in words is "eleven billion, three hundred thirteen million, one hundred twenty-two thousand, one hundred twenty-nine".