Base | Representation |
---|---|
bin | 110100101011100100… |
… | …1011001100001000100 |
3 | 101211000022101000012201 |
4 | 1221113021121201010 |
5 | 3323143043400200 |
6 | 123545522524244 |
7 | 11113332412453 |
oct | 1512711314104 |
9 | 354008330181 |
10 | 113131231300 |
11 | 43a846a357a |
12 | 19b13506684 |
13 | a88c13b4a9 |
14 | 5692dcab9a |
15 | 2e21e5ec6a |
hex | 1a57259844 |
113131231300 has 36 divisors (see below), whose sum is σ = 245583337216. Its totient is φ = 45236167200.
The previous prime is 113131231261. The next prime is 113131231313. The reversal of 113131231300 is 3132131311.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 76429 + ... + 481771.
Almost surely, 2113131231300 is an apocalyptic number.
113131231300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113131231300 is an abundant number, since it is smaller than the sum of its proper divisors (132452105916).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113131231300 is a wasteful number, since it uses less digits than its factorization.
113131231300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 408148 (or 408141 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 113131231300 its reverse (3132131311), we get a palindrome (116263362611).
The spelling of 113131231300 in words is "one hundred thirteen billion, one hundred thirty-one million, two hundred thirty-one thousand, three hundred".
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