Base | Representation |
---|---|
bin | 110100101011100100… |
… | …1110000001001100101 |
3 | 101211000022112201101020 |
4 | 1221113021300021211 |
5 | 3323143104332010 |
6 | 123545524521353 |
7 | 11113333246650 |
oct | 1512711601145 |
9 | 354008481336 |
10 | 113131324005 |
11 | 43a84757197 |
12 | 19b13550259 |
13 | a88c17174b |
14 | 5693012897 |
15 | 2e21e7c470 |
hex | 1a57270265 |
113131324005 has 32 divisors (see below), whose sum is σ = 219037457664. Its totient is φ = 48674989056.
The previous prime is 113131324003. The next prime is 113131324013. The reversal of 113131324005 is 500423131311.
It is not a de Polignac number, because 113131324005 - 21 = 113131324003 is a prime.
It is a super-2 number, since 2×1131313240052 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113131324003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 31687662 + ... + 31691231.
It is an arithmetic number, because the mean of its divisors is an integer number (6844920552).
Almost surely, 2113131324005 is an apocalyptic number.
113131324005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
113131324005 is a deficient number, since it is larger than the sum of its proper divisors (105906133659).
113131324005 is a wasteful number, since it uses less digits than its factorization.
113131324005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63378925.
The product of its (nonzero) digits is 1080, while the sum is 24.
Adding to 113131324005 its reverse (500423131311), we get a palindrome (613554455316).
The spelling of 113131324005 in words is "one hundred thirteen billion, one hundred thirty-one million, three hundred twenty-four thousand, five".
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