Base | Representation |
---|---|
bin | 10101000100101000… |
… | …10000000101010101 |
3 | 1002012102200200111021 |
4 | 22202110100011111 |
5 | 141132131333331 |
6 | 5110332041141 |
7 | 550231131301 |
oct | 124224200525 |
9 | 32172620437 |
10 | 11313152341 |
11 | 4885a85887 |
12 | 22389031b1 |
13 | 10b3a7baaa |
14 | 794708d01 |
15 | 4632ea211 |
hex | 2a2510155 |
11313152341 has 2 divisors, whose sum is σ = 11313152342. Its totient is φ = 11313152340.
The previous prime is 11313152339. The next prime is 11313152351. The reversal of 11313152341 is 14325131311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7422511716 + 3890640625 = 86154^2 + 62375^2 .
It is a cyclic number.
It is not a de Polignac number, because 11313152341 - 21 = 11313152339 is a prime.
It is a super-4 number, since 4×113131523414 (a number of 41 digits) contains 4444 as substring.
Together with 11313152339, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313152321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656576170 + 5656576171.
It is an arithmetic number, because the mean of its divisors is an integer number (5656576171).
Almost surely, 211313152341 is an apocalyptic number.
It is an amenable number.
11313152341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313152341 is an equidigital number, since it uses as much as digits as its factorization.
11313152341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1080, while the sum is 25.
Adding to 11313152341 its reverse (14325131311), we get a palindrome (25638283652).
The spelling of 11313152341 in words is "eleven billion, three hundred thirteen million, one hundred fifty-two thousand, three hundred forty-one".
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