Base | Representation |
---|---|
bin | 10101000100101000… |
… | …10000110101110101 |
3 | 1002012102200211202020 |
4 | 22202110100311311 |
5 | 141132131433240 |
6 | 5110332103353 |
7 | 550231143324 |
oct | 124224206565 |
9 | 32172624666 |
10 | 11313155445 |
11 | 4885a88149 |
12 | 2238904b59 |
13 | 10b3a80327 |
14 | 79470a0bb |
15 | 4632eb0d0 |
hex | 2a2510d75 |
11313155445 has 32 divisors (see below), whose sum is σ = 18580243968. Its totient is φ = 5875258368.
The previous prime is 11313155437. The next prime is 11313155459. The reversal of 11313155445 is 54455131311.
It is a happy number.
It is not a de Polignac number, because 11313155445 - 23 = 11313155437 is a prime.
It is a super-2 number, since 2×113131554452 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 98157 + ... + 179613.
It is an arithmetic number, because the mean of its divisors is an integer number (580632624).
Almost surely, 211313155445 is an apocalyptic number.
11313155445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11313155445 is a deficient number, since it is larger than the sum of its proper divisors (7267088523).
11313155445 is a wasteful number, since it uses less digits than its factorization.
11313155445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81709.
The product of its digits is 18000, while the sum is 33.
Adding to 11313155445 its reverse (54455131311), we get a palindrome (65768286756).
The spelling of 11313155445 in words is "eleven billion, three hundred thirteen million, one hundred fifty-five thousand, four hundred forty-five".
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