Base | Representation |
---|---|
bin | 10000011101100111111… |
… | …100001100000010001111 |
3 | 11000011010122121022020102 |
4 | 100131213330030002033 |
5 | 122013420434330111 |
6 | 2223415450441315 |
7 | 144510112201355 |
oct | 20354774140217 |
9 | 4004118538212 |
10 | 1131320230031 |
11 | 3a687685a422 |
12 | 163310a3323b |
13 | 828b583c374 |
14 | 3ca82dbb7d5 |
15 | 1e66546413b |
hex | 10767f0c08f |
1131320230031 has 2 divisors, whose sum is σ = 1131320230032. Its totient is φ = 1131320230030.
The previous prime is 1131320229971. The next prime is 1131320230043. The reversal of 1131320230031 is 1300320231311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131320230031 - 230 = 1130246488207 is a prime.
It is a super-2 number, since 2×11313202300312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131320229985 and 1131320230012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131320236031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565660115015 + 565660115016.
It is an arithmetic number, because the mean of its divisors is an integer number (565660115016).
Almost surely, 21131320230031 is an apocalyptic number.
1131320230031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131320230031 is an equidigital number, since it uses as much as digits as its factorization.
1131320230031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 1131320230031 its reverse (1300320231311), we get a palindrome (2431640461342).
The spelling of 1131320230031 in words is "one trillion, one hundred thirty-one billion, three hundred twenty million, two hundred thirty thousand, thirty-one".
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