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113132030333 = 741394188259
BaseRepresentation
bin110100101011100110…
…0011100100101111101
3101211000100212121021112
41221113030130211331
53323143244432313
6123545552011405
711113342251140
oct1512714344575
9354010777245
10113132030333
1143a85099933
1219b13830b65
13a88c35b0aa
145693158057
152e2206b8a8
hex1a5731c97d

113132030333 has 8 divisors (see below), whose sum is σ = 132447255360. Its totient is φ = 94605181920.

The previous prime is 113132030311. The next prime is 113132030351. The reversal of 113132030333 is 333030231311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113132030333 - 214 = 113132013949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113132030299 and 113132030308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113132030233) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 197093843 + ... + 197094416.

It is an arithmetic number, because the mean of its divisors is an integer number (16555906920).

Almost surely, 2113132030333 is an apocalyptic number.

It is an amenable number.

113132030333 is a deficient number, since it is larger than the sum of its proper divisors (19315225027).

113132030333 is an equidigital number, since it uses as much as digits as its factorization.

113132030333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 394188307.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 113132030333 its reverse (333030231311), we get a palindrome (446162261644).

The spelling of 113132030333 in words is "one hundred thirteen billion, one hundred thirty-two million, thirty thousand, three hundred thirty-three".

Divisors: 1 7 41 287 394188259 2759317813 16161718619 113132030333