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113132112107 = 716161730301
BaseRepresentation
bin110100101011100110…
…0110000100011101011
3101211000101000202110012
41221113030300203223
53323143310041412
6123545553442135
711113343041430
oct1512714604353
9354011022405
10113132112107
1143a85145313
1219b1387034b
13a88c389391
145693179b87
152e22085c22
hex1a573308eb

113132112107 has 4 divisors (see below), whose sum is σ = 129293842416. Its totient is φ = 96970381800.

The previous prime is 113132112097. The next prime is 113132112127. The reversal of 113132112107 is 701211231311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113132112107 - 26 = 113132112043 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113132112127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8080865144 + ... + 8080865157.

It is an arithmetic number, because the mean of its divisors is an integer number (32323460604).

Almost surely, 2113132112107 is an apocalyptic number.

113132112107 is a deficient number, since it is larger than the sum of its proper divisors (16161730309).

113132112107 is an equidigital number, since it uses as much as digits as its factorization.

113132112107 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16161730308.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 113132112107 its reverse (701211231311), we get a palindrome (814343343418).

The spelling of 113132112107 in words is "one hundred thirteen billion, one hundred thirty-two million, one hundred twelve thousand, one hundred seven".

Divisors: 1 7 16161730301 113132112107