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113132112130 = 2571159341003
BaseRepresentation
bin110100101011100110…
…0110000100100000010
3101211000101000202111001
41221113030300210002
53323143310042010
6123545553442214
711113343041462
oct1512714604402
9354011022431
10113132112130
1143a85145334
1219b1387036a
13a88c3893ab
145693179ba2
152e22085c3a
hex1a57330902

113132112130 has 16 divisors (see below), whose sum is σ = 206505941184. Its totient is φ = 44615480560.

The previous prime is 113132112127. The next prime is 113132112133. The reversal of 113132112130 is 31211231311.

It is an interprime number because it is at equal distance from previous prime (113132112127) and next prime (113132112133).

It is a junction number, because it is equal to n+sod(n) for n = 113132112098 and 113132112107.

It is not an unprimeable number, because it can be changed into a prime (113132112133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79669792 + ... + 79671211.

It is an arithmetic number, because the mean of its divisors is an integer number (12906621324).

Almost surely, 2113132112130 is an apocalyptic number.

113132112130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113132112130 is a deficient number, since it is larger than the sum of its proper divisors (93373829054).

113132112130 is a wasteful number, since it uses less digits than its factorization.

113132112130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159341081.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 113132112130 its reverse (31211231311), we get a palindrome (144343343441).

The spelling of 113132112130 in words is "one hundred thirteen billion, one hundred thirty-two million, one hundred twelve thousand, one hundred thirty".

Divisors: 1 2 5 10 71 142 355 710 159341003 318682006 796705015 1593410030 11313211213 22626422426 56566056065 113132112130