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11313213011303 = 737120373628841
BaseRepresentation
bin1010010010100001000000…
…0010101111010101100111
31111001112101021012020002112
42210220100002233111213
52440323430012330203
640021115053231235
72245231651641560
oct244502002572547
944045337166075
1011313213011303
1136719a78a0165
1213286b019251b
13640aa67b6038
142b17c3451167
15149438d446d8
hexa4a100af567

11313213011303 has 16 divisors (see below), whose sum is σ = 13279935998784. Its totient is φ = 9434171139840.

The previous prime is 11313213011263. The next prime is 11313213011333. The reversal of 11313213011303 is 30311031231311.

It is a cyclic number.

It is not a de Polignac number, because 11313213011303 - 210 = 11313213010279 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313213011333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1303163 + ... + 4932003.

It is an arithmetic number, because the mean of its divisors is an integer number (829995999924).

Almost surely, 211313213011303 is an apocalyptic number.

11313213011303 is a deficient number, since it is larger than the sum of its proper divisors (1966722987481).

11313213011303 is a wasteful number, since it uses less digits than its factorization.

11313213011303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3640922.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 11313213011303 its reverse (30311031231311), we get a palindrome (41624244242614).

The spelling of 11313213011303 in words is "eleven trillion, three hundred thirteen billion, two hundred thirteen million, eleven thousand, three hundred three".

Divisors: 1 7 37 259 12037 84259 445369 3117583 3628841 25401887 134267117 939869819 43680359117 305762513819 1616173287329 11313213011303