Base | Representation |
---|---|
bin | 1010010010100001000000… |
… | …0010101111010101100111 |
3 | 1111001112101021012020002112 |
4 | 2210220100002233111213 |
5 | 2440323430012330203 |
6 | 40021115053231235 |
7 | 2245231651641560 |
oct | 244502002572547 |
9 | 44045337166075 |
10 | 11313213011303 |
11 | 36719a78a0165 |
12 | 13286b019251b |
13 | 640aa67b6038 |
14 | 2b17c3451167 |
15 | 149438d446d8 |
hex | a4a100af567 |
11313213011303 has 16 divisors (see below), whose sum is σ = 13279935998784. Its totient is φ = 9434171139840.
The previous prime is 11313213011263. The next prime is 11313213011333. The reversal of 11313213011303 is 30311031231311.
It is a cyclic number.
It is not a de Polignac number, because 11313213011303 - 210 = 11313213010279 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313213011333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1303163 + ... + 4932003.
It is an arithmetic number, because the mean of its divisors is an integer number (829995999924).
Almost surely, 211313213011303 is an apocalyptic number.
11313213011303 is a deficient number, since it is larger than the sum of its proper divisors (1966722987481).
11313213011303 is a wasteful number, since it uses less digits than its factorization.
11313213011303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3640922.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 11313213011303 its reverse (30311031231311), we get a palindrome (41624244242614).
The spelling of 11313213011303 in words is "eleven trillion, three hundred thirteen billion, two hundred thirteen million, eleven thousand, three hundred three".
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