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113132130323 is a prime number
BaseRepresentation
bin110100101011100110…
…0110101000000010011
3101211000101001200102212
41221113030311000103
53323143311132243
6123545554102335
711113343145512
oct1512714650023
9354011050385
10113132130323
1143a85157a73
1219b1387a9ab
13a88c394764
145693182679
152e2208b318
hex1a57335013

113132130323 has 2 divisors, whose sum is σ = 113132130324. Its totient is φ = 113132130322.

The previous prime is 113132130299. The next prime is 113132130337. The reversal of 113132130323 is 323031231311.

It is a strong prime.

It is an emirp because it is prime and its reverse (323031231311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113132130323 - 220 = 113131081747 is a prime.

It is a super-2 number, since 2×1131321303232 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (113132130343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566065161 + 56566065162.

It is an arithmetic number, because the mean of its divisors is an integer number (56566065162).

Almost surely, 2113132130323 is an apocalyptic number.

113132130323 is a deficient number, since it is larger than the sum of its proper divisors (1).

113132130323 is an equidigital number, since it uses as much as digits as its factorization.

113132130323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 113132130323 its reverse (323031231311), we get a palindrome (436163361634).

The spelling of 113132130323 in words is "one hundred thirteen billion, one hundred thirty-two million, one hundred thirty thousand, three hundred twenty-three".