Base | Representation |
---|---|
bin | 10101000100101000… |
… | …11110111111111101 |
3 | 1002012102210210022002 |
4 | 22202110132333331 |
5 | 141132140312222 |
6 | 5110333232045 |
7 | 550231504361 |
oct | 124224367775 |
9 | 32172723262 |
10 | 11313213437 |
11 | 4886017779 |
12 | 2238932625 |
13 | 10b3aa0846 |
14 | 7947232a1 |
15 | 46330d392 |
hex | 2a251effd |
11313213437 has 2 divisors, whose sum is σ = 11313213438. Its totient is φ = 11313213436.
The previous prime is 11313213413. The next prime is 11313213487. The reversal of 11313213437 is 73431231311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10830356761 + 482856676 = 104069^2 + 21974^2 .
It is a cyclic number.
It is not a de Polignac number, because 11313213437 - 210 = 11313212413 is a prime.
It is a super-3 number, since 3×113132134373 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313213487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656606718 + 5656606719.
It is an arithmetic number, because the mean of its divisors is an integer number (5656606719).
Almost surely, 211313213437 is an apocalyptic number.
It is an amenable number.
11313213437 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313213437 is an equidigital number, since it uses as much as digits as its factorization.
11313213437 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4536, while the sum is 29.
Adding to 11313213437 its reverse (73431231311), we get a palindrome (84744444748).
The spelling of 11313213437 in words is "eleven billion, three hundred thirteen million, two hundred thirteen thousand, four hundred thirty-seven".
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