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11313225203 = 72230882147
BaseRepresentation
bin10101000100101001…
…00001110111110011
31002012102211101102212
422202110201313303
5141132141201303
65110333402335
7550231553600
oct124224416763
932172741385
1011313225203
1148860255a5
1222389393ab
1310b3aa5cc7
147947276a7
15463311ad8
hex2a2521df3

11313225203 has 6 divisors (see below), whose sum is σ = 13160282436. Its totient is φ = 9697050132.

The previous prime is 11313225197. The next prime is 11313225221. The reversal of 11313225203 is 30252231311.

11313225203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11313225203 - 212 = 11313221107 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11313225403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 115441025 + ... + 115441122.

It is an arithmetic number, because the mean of its divisors is an integer number (2193380406).

Almost surely, 211313225203 is an apocalyptic number.

11313225203 is a deficient number, since it is larger than the sum of its proper divisors (1847057233).

11313225203 is an equidigital number, since it uses as much as digits as its factorization.

11313225203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 230882161 (or 230882154 counting only the distinct ones).

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 11313225203 its reverse (30252231311), we get a palindrome (41565456514).

The spelling of 11313225203 in words is "eleven billion, three hundred thirteen million, two hundred twenty-five thousand, two hundred three".

Divisors: 1 7 49 230882147 1616175029 11313225203