11313231213013 has 4 divisors (see below), whose sum is σ = 11313554012928. Its totient is φ = 11312908413100.

The previous prime is 11313231213001. The next prime is 11313231213049. The reversal of 11313231213013 is 31031213231311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11313231213013 - 2⁵ = 11313231212981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313231213073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161347381 + ... + 161417482.

It is an arithmetic number, because the mean of its divisors is an integer number (2828388503232).

Almost surely, 2^{11313231213013} is an apocalyptic number.

It is an amenable number.

11313231213013 is a deficient number, since it is larger than the sum of its proper divisors (322799915).

11313231213013 is an equidigital number, since it uses as much as digits as its factorization.

11313231213013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 322799914.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11313231213013 its reverse (31031213231311), we get a palindrome (42344444444324).

The spelling of 11313231213013 in words is "eleven trillion, three hundred thirteen billion, two hundred thirty-one million, two hundred thirteen thousand, thirteen".