113132320451 has 2 divisors, whose sum is σ = 113132320452. Its totient is φ = 113132320450.

The previous prime is 113132320439. The next prime is 113132320453. The reversal of 113132320451 is 154023231311.

It is a strong prime.

It is an emirp because it is prime and its reverse (154023231311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113132320451 - 2²² = 113128126147 is a prime.

Together with 113132320453, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113132320451.

It is not a weakly prime, because it can be changed into another prime (113132320453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566160225 + 56566160226.

It is an arithmetic number, because the mean of its divisors is an integer number (56566160226).

Almost surely, 2^113132320451 is an apocalyptic number.

113132320451 is a deficient number, since it is larger than the sum of its proper divisors (1).

113132320451 is an equidigital number, since it uses as much as digits as its factorization.

113132320451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 113132320451 its reverse (154023231311), we get a palindrome (267155551762).

The spelling of 113132320451 in words is "one hundred thirteen billion, one hundred thirty-two million, three hundred twenty thousand, four hundred fifty-one".