11313234001 has 4 divisors (see below), whose sum is σ = 11978718372. Its totient is φ = 10647749632.

The previous prime is 11313233999. The next prime is 11313234059. The reversal of 11313234001 is 10043231311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 10043231311 = 16979 ⋅591509.

It can be written as a sum of positive squares in 2 ways, for example, as 7734323025 + 3578910976 = 87945^2 + 59824^2 .

It is a cyclic number.

It is not a de Polignac number, because 11313234001 - 2¹ = 11313233999 is a prime.

It is a super-2 number, since 2×11313234001² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11313234001.

It is not an unprimeable number, because it can be changed into a prime (11313234061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 332742160 + ... + 332742193.

It is an arithmetic number, because the mean of its divisors is an integer number (2994679593).

Almost surely, 2^11313234001 is an apocalyptic number.

It is an amenable number.

11313234001 is a deficient number, since it is larger than the sum of its proper divisors (665484371).

11313234001 is an equidigital number, since it uses as much as digits as its factorization.

11313234001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 665484370.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11313234001 its reverse (10043231311), we get a palindrome (21356465312).

The spelling of 11313234001 in words is "eleven billion, three hundred thirteen million, two hundred thirty-four thousand, one".