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113133100013 is a prime number
BaseRepresentation
bin110100101011101000…
…0100001101111101101
3101211000102212221121022
41221113100201233231
53323144033200023
6123550030543525
711113354324553
oct1512720415755
9354012787538
10113133100013
1143a8575a56a
1219b14067ba5
13a88c643c3b
145693355bd3
152e221cd7c8
hex1a57421bed

113133100013 has 2 divisors, whose sum is σ = 113133100014. Its totient is φ = 113133100012.

The previous prime is 113133100007. The next prime is 113133100027. The reversal of 113133100013 is 310001331311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96834237124 + 16298862889 = 311182^2 + 127667^2 .

It is a cyclic number.

It is not a de Polignac number, because 113133100013 - 26 = 113133099949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113133099964 and 113133100000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113133105013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566550006 + 56566550007.

It is an arithmetic number, because the mean of its divisors is an integer number (56566550007).

Almost surely, 2113133100013 is an apocalyptic number.

It is an amenable number.

113133100013 is a deficient number, since it is larger than the sum of its proper divisors (1).

113133100013 is an equidigital number, since it uses as much as digits as its factorization.

113133100013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 113133100013 its reverse (310001331311), we get a palindrome (423134431324).

The spelling of 113133100013 in words is "one hundred thirteen billion, one hundred thirty-three million, one hundred thousand, thirteen".