Base | Representation |
---|---|
bin | 1010010010100001011000… |
… | …0001010110101001000110 |
3 | 1111001112122020220222211022 |
4 | 2210220112001112221012 |
5 | 2440324131201430202 |
6 | 40021133035111142 |
7 | 2245234310323442 |
oct | 244502601265106 |
9 | 44045566828738 |
10 | 11313313311302 |
11 | 3671a49477022 |
12 | 13287198a24b2 |
13 | 640ac1503252 |
14 | 2b17d28bd822 |
15 | 149442a57ea2 |
hex | a4a16056a46 |
11313313311302 has 4 divisors (see below), whose sum is σ = 16969969966956. Its totient is φ = 5656656655650.
The previous prime is 11313313311271. The next prime is 11313313311331. The reversal of 11313313311302 is 20311331331311.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×113133133113023 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2828328327824 + ... + 2828328327827.
It is an arithmetic number, because the mean of its divisors is an integer number (4242492491739).
Almost surely, 211313313311302 is an apocalyptic number.
11313313311302 is a deficient number, since it is larger than the sum of its proper divisors (5656656655654).
11313313311302 is an equidigital number, since it uses as much as digits as its factorization.
11313313311302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5656656655653.
The product of its (nonzero) digits is 1458, while the sum is 26.
Adding to 11313313311302 its reverse (20311331331311), we get a palindrome (31624644642613).
The spelling of 11313313311302 in words is "eleven trillion, three hundred thirteen billion, three hundred thirteen million, three hundred eleven thousand, three hundred two".
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