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11313313311302 = 25656656655651
BaseRepresentation
bin1010010010100001011000…
…0001010110101001000110
31111001112122020220222211022
42210220112001112221012
52440324131201430202
640021133035111142
72245234310323442
oct244502601265106
944045566828738
1011313313311302
113671a49477022
1213287198a24b2
13640ac1503252
142b17d28bd822
15149442a57ea2
hexa4a16056a46

11313313311302 has 4 divisors (see below), whose sum is σ = 16969969966956. Its totient is φ = 5656656655650.

The previous prime is 11313313311271. The next prime is 11313313311331. The reversal of 11313313311302 is 20311331331311.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×113133133113023 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2828328327824 + ... + 2828328327827.

It is an arithmetic number, because the mean of its divisors is an integer number (4242492491739).

Almost surely, 211313313311302 is an apocalyptic number.

11313313311302 is a deficient number, since it is larger than the sum of its proper divisors (5656656655654).

11313313311302 is an equidigital number, since it uses as much as digits as its factorization.

11313313311302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5656656655653.

The product of its (nonzero) digits is 1458, while the sum is 26.

Adding to 11313313311302 its reverse (20311331331311), we get a palindrome (31624644642613).

The spelling of 11313313311302 in words is "eleven trillion, three hundred thirteen billion, three hundred thirteen million, three hundred eleven thousand, three hundred two".

Divisors: 1 2 5656656655651 11313313311302