Base | Representation |
---|---|
bin | 10101000100101001… |
… | …10111100010001011 |
3 | 1002012102222220011002 |
4 | 22202110313202023 |
5 | 141132202021211 |
6 | 5110335325215 |
7 | 550232403353 |
oct | 124224674213 |
9 | 32172886132 |
10 | 11313313931 |
11 | 4886086227 |
12 | 223898080b |
13 | 10b3b074ca |
14 | 79474bb63 |
15 | 46332d03b |
hex | 2a253788b |
11313313931 has 2 divisors, whose sum is σ = 11313313932. Its totient is φ = 11313313930.
The previous prime is 11313313903. The next prime is 11313313933. The reversal of 11313313931 is 13931331311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11313313931 - 226 = 11246205067 is a prime.
It is a super-2 number, since 2×113133139312 (a number of 21 digits) contains 22 as substring.
Together with 11313313933, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 11313313894 and 11313313903.
It is not a weakly prime, because it can be changed into another prime (11313313933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656656965 + 5656656966.
It is an arithmetic number, because the mean of its divisors is an integer number (5656656966).
Almost surely, 211313313931 is an apocalyptic number.
11313313931 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313313931 is an equidigital number, since it uses as much as digits as its factorization.
11313313931 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2187, while the sum is 29.
The spelling of 11313313931 in words is "eleven billion, three hundred thirteen million, three hundred thirteen thousand, nine hundred thirty-one".
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