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11313318127997 is a prime number
BaseRepresentation
bin1010010010100001011001…
…0011101110100101111101
31111001112122120222201002102
42210220112103232211331
52440324133420043442
640021133330234445
72245234366264334
oct244502623564575
944045576881072
1011313318127997
113671a51166966
12132871b425a25
13640ac24cb772
142b17d33b4d1b
151494431aa232
hexa4a164ee97d

11313318127997 has 2 divisors, whose sum is σ = 11313318127998. Its totient is φ = 11313318127996.

The previous prime is 11313318127973. The next prime is 11313318128017. The reversal of 11313318127997 is 79972181331311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6306155574436 + 5007162553561 = 2511206^2 + 2237669^2 .

It is a cyclic number.

It is not a de Polignac number, because 11313318127997 - 212 = 11313318123901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11313318627997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656659063998 + 5656659063999.

It is an arithmetic number, because the mean of its divisors is an integer number (5656659063999).

Almost surely, 211313318127997 is an apocalyptic number.

It is an amenable number.

11313318127997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313318127997 is an equidigital number, since it uses as much as digits as its factorization.

11313318127997 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1714608, while the sum is 56.

The spelling of 11313318127997 in words is "eleven trillion, three hundred thirteen billion, three hundred eighteen million, one hundred twenty-seven thousand, nine hundred ninety-seven".