Base | Representation |
---|---|
bin | 11001101110010011100000… |
… | …010100110010101000100111 |
3 | 112211120102120101010000120101 |
4 | 121232103200110302220213 |
5 | 104312033244220421203 |
6 | 1040340401531044531 |
7 | 32554414133243515 |
oct | 3156234024625047 |
9 | 484512511100511 |
10 | 113133202123303 |
11 | 3305858124969a |
12 | 10831b805a0747 |
13 | 4b18552208cab |
14 | 1dd19676c14b5 |
15 | d12cc2e8741d |
hex | 66e4e0532a27 |
113133202123303 has 4 divisors (see below), whose sum is σ = 113133300229080. Its totient is φ = 113133104017528.
The previous prime is 113133202123301. The next prime is 113133202123339. The reversal of 113133202123303 is 303321202331311.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113133202123303 - 21 = 113133202123301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113133202123301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47302300 + ... + 49636417.
It is an arithmetic number, because the mean of its divisors is an integer number (28283325057270).
Almost surely, 2113133202123303 is an apocalyptic number.
113133202123303 is a deficient number, since it is larger than the sum of its proper divisors (98105777).
113133202123303 is an equidigital number, since it uses as much as digits as its factorization.
113133202123303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98105776.
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 113133202123303 its reverse (303321202331311), we get a palindrome (416454404454614).
The spelling of 113133202123303 in words is "one hundred thirteen trillion, one hundred thirty-three billion, two hundred two million, one hundred twenty-three thousand, three hundred three".
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