Base | Representation |
---|---|
bin | 10101000100101001… |
… | …11001000111111001 |
3 | 1002012110000020002012 |
4 | 22202110321013321 |
5 | 141132202223231 |
6 | 5110335415305 |
7 | 550232431343 |
oct | 124224710771 |
9 | 32173006065 |
10 | 11313320441 |
11 | 4886090105 |
12 | 2238984535 |
13 | 10b3b0a467 |
14 | 794750293 |
15 | 46332ee2b |
hex | 2a25391f9 |
11313320441 has 2 divisors, whose sum is σ = 11313320442. Its totient is φ = 11313320440.
The previous prime is 11313320419. The next prime is 11313320449. The reversal of 11313320441 is 14402331311.
11313320441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5790601216 + 5522719225 = 76096^2 + 74315^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11313320441 is a prime.
It is not a weakly prime, because it can be changed into another prime (11313320449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656660220 + 5656660221.
It is an arithmetic number, because the mean of its divisors is an integer number (5656660221).
Almost surely, 211313320441 is an apocalyptic number.
It is an amenable number.
11313320441 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313320441 is an equidigital number, since it uses as much as digits as its factorization.
11313320441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 11313320441 its reverse (14402331311), we get a palindrome (25715651752).
The spelling of 11313320441 in words is "eleven billion, three hundred thirteen million, three hundred twenty thousand, four hundred forty-one".
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