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113133233010101 is a prime number
BaseRepresentation
bin11001101110010011100010…
…001010100111010110110101
3112211120102122112020020021212
4121232103202022213112311
5104312033330122310401
61040340404553051205
732554414656624503
oct3156234212472665
9484512575206255
10113133233010101
1133058597725377
1210831b8a9b6b05
134b185587317c5
141dd196b841673
15d12cc5a38dbb
hex66e4e22a75b5

113133233010101 has 2 divisors, whose sum is σ = 113133233010102. Its totient is φ = 113133233010100.

The previous prime is 113133233010097. The next prime is 113133233010121. The reversal of 113133233010101 is 101010332331311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76347855651076 + 36785377359025 = 8737726^2 + 6065095^2 .

It is a cyclic number.

It is not a de Polignac number, because 113133233010101 - 22 = 113133233010097 is a prime.

It is a super-2 number, since 2×1131332330101012 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113133233010121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566616505050 + 56566616505051.

It is an arithmetic number, because the mean of its divisors is an integer number (56566616505051).

Almost surely, 2113133233010101 is an apocalyptic number.

It is an amenable number.

113133233010101 is a deficient number, since it is larger than the sum of its proper divisors (1).

113133233010101 is an equidigital number, since it uses as much as digits as its factorization.

113133233010101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 113133233010101 its reverse (101010332331311), we get a palindrome (214143565341412).

The spelling of 113133233010101 in words is "one hundred thirteen trillion, one hundred thirty-three billion, two hundred thirty-three million, ten thousand, one hundred one".