Base | Representation |
---|---|
bin | 110100101011101000… |
… | …1010111011110110101 |
3 | 101211000110022010112022 |
4 | 1221113101113132311 |
5 | 3323144112220432 |
6 | 123550035402525 |
7 | 11113356232346 |
oct | 1512721273665 |
9 | 354013263468 |
10 | 113133320117 |
11 | 43a8589a974 |
12 | 19b14153445 |
13 | a88c6c018c |
14 | 56933b20cd |
15 | 2e22223b12 |
hex | 1a574577b5 |
113133320117 has 2 divisors, whose sum is σ = 113133320118. Its totient is φ = 113133320116.
The previous prime is 113133320093. The next prime is 113133320123. The reversal of 113133320117 is 711023331311.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67163387281 + 45969932836 = 259159^2 + 214406^2 .
It is a cyclic number.
It is not a de Polignac number, because 113133320117 - 224 = 113116542901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113133320017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566660058 + 56566660059.
It is an arithmetic number, because the mean of its divisors is an integer number (56566660059).
Almost surely, 2113133320117 is an apocalyptic number.
It is an amenable number.
113133320117 is a deficient number, since it is larger than the sum of its proper divisors (1).
113133320117 is an equidigital number, since it uses as much as digits as its factorization.
113133320117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 26.
Adding to 113133320117 its reverse (711023331311), we get a palindrome (824156651428).
The spelling of 113133320117 in words is "one hundred thirteen billion, one hundred thirty-three million, three hundred twenty thousand, one hundred seventeen".
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